x=x^2+2x+65

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Solution for x=x^2+2x+65 equation: 



x=x^2+2x+65

We move all terms to the left:

x-(x^2+2x+65)=0

We get rid of parentheses

-x^2+x-2x-65=0

We add all the numbers together, and all the variables

-1x^2-1x-65=0

a = -1; b = -1; c = -65;
Δ = b2-4ac
Δ = -12-4·(-1)·(-65)
Δ = -259
Delta is less than zero, so there is no solution for the equation

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